Question: We
have to ask user to enter number or string he/she wants, and give output is number/string Palindrome or not?
(abcba-Palindrome String)
(abccba-Palindrome String)
(12321-Palindrome Number)
(123321-Palindrome Number)
Answer: Copy the below code and paste it into "your.php" file. After done this you will just need to run "your.php" file in browser and you will get the output successfully.
(abcba-Palindrome String)
(abccba-Palindrome String)
(12321-Palindrome Number)
(123321-Palindrome Number)
Answer: Copy the below code and paste it into "your.php" file. After done this you will just need to run "your.php" file in browser and you will get the output successfully.
<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Palindrome number or string</title>
</head>
<body>
<h1><center>Palindrome number or string</center></h1>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
Enter number or string:<input type="text" name="num"/>
<input type="submit" name="submit" value="OK" />
</form>
<?php
if (isset($_POST['submit'])) {
$num = $_POST['num'];
$numeric = is_numeric($num);
function is_palindrome(&$str) {
for ($i = 0; $i < strlen($str) / 2; $i++) {
if ($str[$i] != $str[strlen($str) - 1 - $i])
return false;
}
return true;
}
if (!$numeric) {
$result = is_palindrome($num);
if ($result) {
echo $num . " is palindrome string";
}
else
echo $num . " is not palindrome string";
} else {
$sum = 0;
$temp = $num;
while ($temp >= 1) {
$r = $temp % 10;
$temp = $temp / 10;
$sum = $sum * 10 + $r;
}
if ($sum == $num) {
echo $num . " is palindrome number";
}
else
echo $num . " is not palindrome number";
}
}
?>
</body>
</html>
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